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Calculus · AP · Test Prep

Differential Equations I: First and Second Order

Separable, linear and exact equations, integrating factors, constant coefficient second order equations and undetermined coefficients.

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39 basic cards for AP Calculus. Set 1 of 2 in Differential Equations. It opens with "What is a separable differential equation?" and "Write the standard form of a separable equation". Study it alongside the other AP sets below.

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What is a separable differential equation?
Show answerAn equation where the variables can be separated to opposite sides, written as M(x)dx + N(y)dy = 0
Write the standard form of a separable equation
Show answerM(x)dx + N(y)dy = 0
What is the key procedure to solve dy/dx = f(x)g(y)?
Show answerSeparate variables: dy/g(y) = f(x)dx, then integrate both sides
Solve dy/dx = y by separable method
Show answerSeparate: dy/y = dx, integrate: ln|y| = x + C, so y = Ae^x
Can y = 0 be a singular solution to a separable equation?
Show answerYes, if it satisfies the original equation but does not appear in the general solution for any value of C
For dy/dx = 2xy, find the solution by separating variables
Show answerdy/y = 2x dx, integrate: ln|y| = x² + C, so y = Ae^(x²)
When solving a separable equation, what must you remember about constants of integration?
Show answerYou only need one arbitrary constant C on one side after integrating both sides
What form does the solution to a separable equation typically take?
Show answerAn implicit relation F(x) + G(y) = C, which may or may not be solvable for y explicitly
Write the standard form of a first-order linear differential equation
Show answerdy/dx + P(x)y = Q(x)
What is an integrating factor?
Show answerA function u(x) that, when multiplied by a linear equation, makes it exact (or a total derivative)
Give the formula for the integrating factor of dy/dx + P(x)y = Q(x)
Show answeru(x) = e^(∫P(x)dx)
After multiplying dy/dx + P(x)y = Q(x) by integrating factor u(x), what does the left side become?
Show answerd/dx[u(x)y], which is a total derivative
After using an integrating factor on dy/dx + P(x)y = Q(x), how do you solve for y?
Show answerIntegrate both sides: u(x)y = ∫u(x)Q(x)dx + C, then divide by u(x)
Solve dy/dx - 2y = 0 using an integrating factor
Show answerIntegrating factor: u(x) = e^(-2x). Then e^(-2x)y = C, so y = Ce^(2x)
What test determines if an equation M(x,y)dx + N(x,y)dy = 0 is exact?
Show answerThe equation is exact if and only if ∂M/∂y = ∂N/∂x

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